Question

An observer 1.5m tall is 20.5m away from Tower 27m high. Determine The angle of elevation of the top of the tower from the eye of the observer

Answer 1

Difference in the height of the observer and the tower = 27 - 1.5 = 25.5 m

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Distance of the observer from the tower = 20.5 m (Given)

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$\boxed {\tan(\theta) = \dfrac{\text{opp}}{\text{adj}} }$

$\tan(\theta) = \dfrac{\text{25.5}}{\text{20.5}}$

$\theta = 51.2 \textdegree$

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Answer: The angle of elevation is 51.2°

Answer 2

Answer:

Lol

Step-by-step explanation: