An observer 1.5m tall is 28.5 away from a tower 30m high .determine the angle of top of elevation of the top of rhe tower from hiIs eye
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the height of tower = 30m..
the distance of observer =28.5....m
the height of observer..= 1.5m
the angle of elevation is....
total. height of tower..= height of tower-height of observer...
(30-1.5..)m
=28.5m
tan theta= total height/distance of observer from tower...
= 28.5/28.5 = tan45°...
theta = 45°.....
the distance of observer =28.5....m
the height of observer..= 1.5m
the angle of elevation is....
total. height of tower..= height of tower-height of observer...
(30-1.5..)m
=28.5m
tan theta= total height/distance of observer from tower...
= 28.5/28.5 = tan45°...
theta = 45°.....
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