Question

An observer 1.5m tall is 28.5m away from a tower 30m height .Find the angle of elevation of the top of the tower his eye​

Answer 1

Answer:

let , the height of observer AB=1.5m

height of tower PQ= 30m

distance between them is BQ= 28.5m

30 - 1.5=28.5m

so angles of elevation = tan45= 28.5/28.5= 1

hence angles of elevation =45°