Question

An observer 1.7 m tall is 20 root 3 away from a tower. Find the angle of elevation from the eye of the observer to the top of the tower, if the height of the tower is 21.7 m.​

Answer 1

Answer:

Let AD is the height of the tower.

AD = 21.7 m

CE be the height of the observer.

CE = BD = 1.7 m

AD - BD = AB

21.7 - 1.7 = 1 m

AB = 1 m

CB = 20 sqrt 3 = ED

Theta is the Angle of elevation made by base CB and Perpendicular AB.

Tan theta = Perpendicular / Base = AB / CB

Tan theta = 1 / 20 sqrt 3

Tan theta = (1/ 20) ( 1/sqrt 3)

Tan theta = Tan 30 ( 1/ 20)

Theta = 30 / 20 = 1.5 °

Theta = 1.5 °

Answer 2

Answer:

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