Question

an observer 1.7 M tall tall 20 root 3 M away from a tower the angle of elevation from the eye of the observer to the top of a tower is 30 degree find the height of the tower

Answer 1

Solution :-

Let AB be the height of the tower and DE be the height of the observer. 

Then, 

In Δ ACD ,

AC/DC = tan 30°

⇒ x/√30 = tan 30° = 1/√3 

⇒ x = 20 m

AB = 20 m + 1.7 m

= 21.7 m

So, the height of the tower is 21.7 m

Answer. 

Answer 2

Hope it helps you!

Regards,

Shobana