an observer and a vehicle both start moving together from rest with acc 5 m/s^2 and 2 m/s^2 in same directions .there is a 2 kg block on the floor of the vehicle and coeff of friction is 0.3 betwwen their surfaces . find the work done by the frictional force on the block as observed by the running observer during first 2 secinds of motion ?
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The relative acceleration for the car is :
Acceleration = 5 - 2 = 3 m/s²
The block is also moving with the same acceleration.
The frictional force equals :
F = ωma
Where :
m = mass
ω = coefficient of kinetic friction.
a = acceleration due to gravity.
Now doing the substitution we have :
F = 0.3 × 3 × 2 = 1.8 N
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