An observer finds the angle of elevation of the top of a pole to be 60°. If the height of the pole and the observer are 25.3 m and 1.3 m respectively, find the distance between the observer and the pole.
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Here Work done=Heat
Current=I=10A
Time=t=10s
Potential difference=V=15V
We know
\boxed{\sf Heat=VIt}
Heat=VIt
\begin{gathered}\\ \sf\longmapsto H=15\times 10\times 10\end{gathered}
⟼H=15×10×10
\begin{gathered}\\ \sf\longmapsto H=15\times 100\end{gathered}
⟼H=15×100
\begin{gathered}\\ \sf\longmapsto H=1500J\end{gathered}
⟼H=1500J
Work done here is 1500Joules
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Hey friend sorry, but I really don't know the answer
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