Question

An observer from the top of a light house, 100 m high above sea level, observes the
angle of depression of a ship, sailing directly towards him, changes from 30° to 60°.
Determine the distance travelled by the ship during the period of observation.​

Answer 1

Answer:

100/ROOT 3 - 100 ROOT 3

Step-by-step explanation:

1. Take triangle ABC opp/hyp
2. $\tan(60)$
3. $\sqrt{3}$

• tan 60 = opp/hyp =AB/BC
• AB=100m
• SO, 100/BC=ROOT 3

BC= 100 /ROOT 3M

NOW IN TRIANGLE AB/BD=TAN 30 =1/ROOT3

100/BD=1/ROOT 3

BD = 100 ROOT 3

NOW, DISTANCE TRAVELLED = BC-BD = 100/ROOT 3- 100 ROOT 3 M