Question

An observer in air at a distance of 0.8m from the surface of water looks at a fish inside the water at a distance of 1.4m.Calculate actual distance of the fish from the observer​

Answer 1

Explanation:

apparent position of fish for observer is 1.4 m.

actual position is = refractive index of water x apparent position.

actual position = 4/3 x 1.4

distance =( 0.8 + 5.6/3 )m = 0.8 + 1.8 = 2.6m

Answer 2

Answer:

The actual distance of the fish from the observer​ is 2.67m.

Explanation:

Given:

Distance of the observer(s)0.8m

Apparent depth=1.4m

Refractive index of water=4/3

To find:

The actual distance of the fish=?

Solution:

We know that,

$RI=\frac{Real depth }{Apparent depth}$

4/3=Real depth/1.4

∴Real depth=(4×1.4)/3=1.87m

The actual distance=s+1.87

∴0.8+1.87=2.67m

Therefore, the actual distance of the fish from the observer​ is 2.67m.