Question

an observer is at distance r metre from an isotropic point ligut source whose power is H watt. the rms value of electric field at the position of observer is​

Answer 1

Answer:

RMS value of electric field at distance r from the source is given as

$E_{rms} = \sqrt{\frac{H}{4\pi \epsilon_o r^2}}$

Explanation:

As we know that intensity of the source at a distance "r" from it is given as

$I = \frac{P}{4\pi r^2}$

so we will have

$I = \frac{H}{4\pi r^2}$

now we know that intensity of the wave is given as

$I = \frac{1}{2}\epsilon_0 E_o^2$

$\frac{H}{4\pi r^2} = \epsilon_0 E_{rms}^2$

now we have

$E_{rms} = \sqrt{\frac{H}{4\pi \epsilon_o r^2}}$

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Topic : electromagnetic waves

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Answer 2

Answer:

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