Question

an observer is moving with speed v° towards a stationary source emitting a sound wave of wavelength lambda the change in wavelength detected by the observer is (v=speed of sound)​

Answer 1

Answer:

In this case there is no change in wavelength detected by the observer

Explanation:

As we know that when source and observer moves relative to each other than the frequency observed by the observer is different from actual frequency

So we can say when observer is moving towards stationary observer then the apparent frequency is given as

$f_{app} = f_o(\frac{v + v_o}{v})$

now the apparent wavelength is given as

$\lambda_{app} = \frac{v + v_o}{f_{app}}$

here we will have

$\lambda_{app} = \frac{v + v_o}{f_o(\frac{v + v_o}{v})}$

$\lambda_{app} = \frac{v}{f_o}$

so apparent wavelength is same as real wavelength

So in this case there is no change in wavelength detected by the observer

#Learn

Topic : Doppler's Effect

https://brainly.in/question/8572534

Answer 2

Doppler effect deals only with relative motion of the observer and source thus no change in wavelength will occur

hope it help