Question

an observer is standing 58.5 m away from a tower 60 m high .the angle of elevation from his eye to the top of the tower is 45° , find the height of observer.​

Answer 1

Step-by-step explanation:

ANSWER

We can form the above figure by given data

⟹BD=CE=1.5

In ΔABC,∠CBA=90

o

⟹tan45

o

=

BC

AB

⟹1=

28.5

AB

⟹AB=28.5

Now, h=AB+BD=28.5+1.5=30

Hence, height of the tower is 30 m

solution