Question

An observer is standing inside a lift moving upwards with an acceleration A . A mass m is lying on the floor of the
lift. Find the normal reaction between the block and the floor.​

Answer 1

AnSwer :-

$\bigstar$Analysis of motion of mass m by the observer S In the frame of lift, N and Mg (real forces) and mA (pseudo force) act on m As block is at rest relative to lift these forces must balance each other.

For the observer S

The acceleration of mass m = acceleration of m relative to the lift = 0 m/s² . Force diagram of m from inside the lift will include normal reaction, weight and a pseudo force of magnitude mA acting opposite to the acceleration of the lift.

Upward force = downward force

$\boxed { \bf N = mg + mA}$

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