Physics, asked by afrinsiddique83, 21 days ago

An observer noticed that a flash of a light of a distance fireworks occurred 2.4 sec before he heard the sound. How far is he from the firework?[Take speed of sound in air= 340m/s].​

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Answers

Answered by student8961
3

Answer:

He is 816 m away from the firework.

Explanation:

Q. An observer noticed that a flash of a light of a distance fireworks occurred 2.4 sec before he heard the sound. How far is he from the firework?[Take speed of sound in air= 340m/s].

Solution:

Given,

• Time(T) = 2.4 sec

• Time(T) = 2.4 sec• Speed(S) = 340m/s

To find : distance (D)

We know,

Speed (S) = Time (T) ÷ Distance (D)

Therefore, from the above formula, we can say:

D = S X T

After substituting the values, we get:

D = 340m/s X 2.4 sec

= 816 m.

Answered by SanskratiJoshi
0

Given: Time before he heard the sound of the fireworks- 2.4 sec.

To Find: Distance of the observer from the firework.

Solution: Time = 2.4 seconds.

Speed of air= 340m/s. (according to the question)

According to the formula,

Speed = Distance/ Time.

which means, Distance = Speed×Time.

putting the values of speed and time,

we have,

Distance = 340m/s × 2.4s.

Distance = 816m

Hence, the distance between the observer and the fireworks is 816 metres.

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