An observer noticed that a flash of a light of a distance fireworks occurred 2.4 sec before he heard the sound. How far is he from the firework?[Take speed of sound in air= 340m/s].
Answers
Answer:
He is 816 m away from the firework.
Explanation:
Q. An observer noticed that a flash of a light of a distance fireworks occurred 2.4 sec before he heard the sound. How far is he from the firework?[Take speed of sound in air= 340m/s].
Solution:
Given,
• Time(T) = 2.4 sec
• Time(T) = 2.4 sec• Speed(S) = 340m/s
To find : distance (D)
We know,
Speed (S) = Time (T) ÷ Distance (D)
Therefore, from the above formula, we can say:
D = S X T
After substituting the values, we get:
D = 340m/s X 2.4 sec
= 816 m.
Given: Time before he heard the sound of the fireworks- 2.4 sec.
To Find: Distance of the observer from the firework.
Solution: Time = 2.4 seconds.
Speed of air= 340m/s. (according to the question)
According to the formula,
Speed = Distance/ Time.
which means, Distance = Speed×Time.
putting the values of speed and time,
we have,
Distance = 340m/s × 2.4s.
Distance = 816m
Hence, the distance between the observer and the fireworks is 816 metres.