an observer sitting in between two vertical walls claps 10 times per second. he adjusts his distance 17m from one wall in such a way that the sound of his clapping coincides with the echo. calculate the velocity of sound
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Given: d = 17.5m
An observer claps 10 times in one second, i.e., he claps at an interval of 1/10th of a second or 0.1 s. As the sound of the echo coincides with the clap this means that the echo is heard after 0.1s.
Therefore, t = 0.1s
v = 2d/t = 2 x 17s/0.1 = 350 m/s.
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