Question

An observer sitting in line of two tanks, watches the flashes of two tanks firing at each other at the same time, but he hears the sounds of two shots 2 s and 3.5 s after seeing the flashes. If distance between the two tanks is 510 m, find the speed of sound.

Answer 1

Answer:

Speed of the sound is 340 m/s

Explanation:

Let the speed of sound is "v" and the distance of the observer from the nearer tank is L

so we have

$t_1 = \frac{L}{v}$

and

$t_2 = \frac{L + 510}{v}$

here we know that

$t_1 = 2 s$ & $t_2 = 3.5 s$

now we have

$2 = \frac{L}{v}$

$3.5 = \frac{L + 510}{v}$

so we have

$\frac{3.5}{2} = \frac{L + 510}{L}$

$3.5 L = 2L + 1020$

$1.5 L = 1020$

$L = 680$

Now speed of sound is given as

$v = \frac{680}{2}$

$v = 340 m/s$

#Learn

Topic : Kinematics

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