Question

An observer standing near a window 5 m high observe that an object falling downwards is passing across the window in 0.5 s. Find at what height above the window the object was dropped. (g = 10 m/s2 ).​

Answer 1

Answer:

Diffusion refers to the net movement of atoms or molecules from regions of high concentration to regions of low concentration. Molecules or atoms will move from regions of high concentration to regions of low concentration due to random particle movement, which results in a change in the concentration gradient of a sample

Answer 2

Answer:

An object in free fall, NOT experiencing parabolic motion, has an equation of

h(t)=\frac{1}{2} gt^2+h_0 which says:

The height of an object with respect to time in seconds is equal to the pull of gravity times time-squared plus the height from which it was dropped. Normally we use -9.8 for gravity but you said to use 10, so be it.

For us, h(t) is 5 because we are looking for the height of the window when the object is 5 m off the ground at .5 seconds;

g = 10 m/s/s, and

t = .5sec

5=\frac{1}{2}(-10)(.5)^2+h and

5 = -5(.5)² + h and

5 = -5(.25) + h and

5 = -1.25 + h so

h = 6.25

That’s how high the window is above the ground.