Question

An observer standing on top of a vertical spots a house in the adjacent valley at an angle of depression of 12 degree the Cliff is 60 meter tall how for is the house from the base of the cliff

Answer 1

Distance between the house and the base of the cliff is 282.27 m.

Step-by-step explanation:

From the figure attached,

AB = Height of the cliff = 60 m

Let the distance between the base of the cliff and the house 'C' = x m

If the angle of depression = 12°

Then angle of elevation of the top of the cliff from the house = 12°

Now from right triangle ABC,

tan12° = $\frac{60}{x}$

x = $\frac{60}{\text{tan12}}$

x = $\frac{60}{0.21256}$

x = 282.27 m

Therefore, distance of the house from the base of the cliff is 282.27 m.

Practice more similar problems from https://brainly.in/question/1661241

Answer 2

the cliff is $282.27 m.$

Step-by-step explanation:

From the figure attached,

AB = Height of the cliff $= 60 m$

Let the distance between the base of the cliff and the house $'C' = x m$

If the angle of depression = 12°

Then angle of elevation of the top of the cliff from the house $= 12^\circ$

Now from right triangle ABC,

$tan12^\circ = \frac{60}{x}$

$x = \frac{60}{tan 12}$

$x = \frac{60}{0.21256}$

$x = 282.27 m$

Therefore, a distance of the house from the base of the cliff is $282.27 m.$

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