Question

an observer with a mass 10kg moves at aconstant velocity of 10 m/s. a constant force then acts for 4 seconds on the object and givesit a speed of 2m/s in opposite direction The acceleration produced in it is

Answer 1

Change in velocity

-2-10=-12

Time required is 4 seconds

a=Δv/t

=-12/4

=-3 m/s²

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Answer 2

ⓗⓞⓛⓛⓐ ⓜⓐⓣⓔ ❤

Change in velocity

-2-10=-12

Time required is 4 seconds

a=Δv/t

=-12/4

=-3 m/s²

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