An octagon has three equal angles each of measure 115.if all the remaining angles have equal measure find the measure of each of these remaining angles?
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Step-by-step explanation:
Sum of measure of angles of polygon is calculated by the formula,
sum = (n - 2) × 180° where n is the number of sides.
For an octagon,
n = 8
Therefore,
sum of all angles = (8 - 2)×180°
= 6 × 180°
= 1080°
Given,
the octagon has three angles of 115° each.
Sum of three angle = 115 × 3
= 345°
Now, there are 5 remaining angles. It is given that these remaining angles are equal.
So, Let the measure of one angle be x.
Then,
Measure of remaining 5 angles = 5x
We have already calculated the sum of all angles.
Therefore,
5x + 345° = 1080°
5x = 735°
x = 147°
Therefore, each of the remaining angles have a measure of 147°.
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