An octagon has two equal angle is 120 degree and all the remaining 6 angles are equal find the measures of each of the six equal angles
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sum of all angles of octagon=1080degree.
octagon=8 Angles
2 angle= 120 degree
sum of this 2 angle=2×120=240
remaining sides=8-2=6angles
remaining angle measurement=1080-240=840
now, let's consider remaining 6 angles as 6a and remaining 840 degree
6a=840
a=840÷6
a=140 degree.
therefore, the measurement of remaining angles=140 degrees
proof=
140 ×6 +240
=1080 proved
octagon=8 Angles
2 angle= 120 degree
sum of this 2 angle=2×120=240
remaining sides=8-2=6angles
remaining angle measurement=1080-240=840
now, let's consider remaining 6 angles as 6a and remaining 840 degree
6a=840
a=840÷6
a=140 degree.
therefore, the measurement of remaining angles=140 degrees
proof=
140 ×6 +240
=1080 proved
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