An odd two-digit number ,difference of whose digits is 8 and sum of the digits is 10,is
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Answer:
Step-by-step explanation:
Let the digits be x and y
A/Q,
x-y = 8
And, x+y = 10
Adding both the equations:
2x = 18
x = 9
Now , placing x = 9 in equation 1 :
9 - y = 8
-y = -1
y = 1
Therefore , the possible no.s can be xy or yx i.e. 19 or 91.
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