Question

An off-season discount of x% is being offered at the
discount store. An additional 12.5% discount is given
if the value of purchase is more than Rs. 500. After
the discounts, a person pays Rs. 525 for a jean whose
list price is Rs. 750. Find the value of x.​

Answer 1

Answer:

20%

Step-by-step explanation:

Mp = 750

Sp = 525

Sp/Mp = 525/750 = 7/10

Overall discount = [(10-7)/10] × 100 = 30%. (1)

Now effective discount of x% and 12.5% is

x + 12.5 - x*12.5/100 = 30. [from (1)]

87.5x/100 = 17.5

x = 1750/87.5 = 20%

Answer 2

The value of x is 20%.

Given,

Off-season discount of x%.

Additional discount of 12.5%.

Selling Price = Rs.525

Marked Price = Rs.750

To Find,

The value of x.

Solution,

The marked price of jeans = Rs.750

New Selling Price of the jeans = Rs.525.

Off-season discount = 100-x

Additional discount = 100 - 12.5.

Let's solve the question using the given information,

= 750 ×$\frac{(100-12.5)}{100}$×$\frac{(100-x)}{100}$.

⇒ (100-x) = $\frac{525}{750}$ ×$\frac{100}{87.5}$ × 100 = 80

⇒ 100 - x = 80

⇒ x = 100 - 80

⇒ x = 20%.

The value of x is 20%.

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