Physics, asked by jaybhayepratik8, 1 year ago

An office goer starts from his house with a speed of 4 km/h and reaches the office 5 minutes
late. Next day he increases speed by 1 km/h and reaches the office 5 minutes earlier. The
distance between his house and office is​

Answers

Answered by sanjaykumar94
4

Explanation:

First change 4km/h into km/min

it will be 4by60 km/min

Now apply the formulae

Distance= speed × time

Distance= 4 by 60 km/min × 5 min

hence answer will be

1by3 km

HOPE ANSWER WAS HELPFUL.

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