An office has 8 officers including two who are twins. Two teams, red and blue, of 4 officers each are to be formed randomly. What is the probability that the twins would be together in the red team?
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Answer:
the probability that the twins would be together in the red team = 3/14
Step-by-step explanation:
An office has 8 officers including two who are twins. Two teams, red and blue, of 4 officers each are to be formed randomly.
Total 8 officers
4 officers in a group
Number of ways the red group can be formed = ⁸C₄
= 8!/(4!4!)
= 8 * 7 * 6 * 5 / ( 4 * 3 * 2 * 1)
= 70
Lets make a group of twins
Now three officers to be selected 1T , 2 other officers
2 other officers need to be selected from 6 officers = ⁶C₂
= 6!/(4!2!)
= 6 * 5/(2*1)
= 15
the probability that the twins would be together in the red team = 15/70
= 3/14
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