Math, asked by anonymous3839739, 1 month ago

An office has n employees. Every employee likes at least one of tea, coffee and
milk. The number of employees who like only tea, only coffee, only milk and all
the three are all equal. The number of employees who like only tea and coffee, only
coffee and milk and only milk and tea are equal and each is equal to half the number
of employees who like all the three. Find the "minimum" value that n can take?

Answers

Answered by Anonymous
2

Answer:

An office has n employees. Every employee likes at least one of tea, coffee and

milk. The number of employees who like only tea, only coffee, only milk and all

the three are all equal. The number of employees who like only tea and coffee, only

coffee and milk and only milk and tea are equal and each is equal to half the number

of employees who like all the three. Find the "minimum" value that n can take?

Answered by rohithkrhoypuc1
2

Answer:

Hello mate,

☆Here your answer to the question: -

Let the number people who like all the three be donated by x

A union B unionC= nA+nB+nC- n (A union B )-n(A intersection C )-n (B intersection C) +A intersection B intersection C

= 4x+4x+4x- 2x-2x-2x+x

= 12x-6x +x

= 7x .

Therefore total number of people divisible by 7 which we can see that only true in the case of 77.

Hope it helps u mate

Mark it as BRAINLIEAST please i request

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