Physics, asked by sales6070, 1 year ago

An ohmic conductor of circular cross-section has a resistance R. If it is melted and recast to half of its length with rectangular cross-section, its new resistance will be

Answers

Answered by nidaeamann
75

Answer:

R’= ¼ x R

Explanation:

Resistance of a wire is given as;

R = pL/A

Where p is the resistivity of wire. It will be same for same material

A is the cross sectional area

L is the length.

Now if the wire is recasted, such that the length is halved then, the area will also change because the overall volume has to be the same.

V’=V

A’ x L’ = A x L

When L’ = L/2

This means that area becomes;

A’ = 2 x A

Calculating new resistance of wire after it is recasted;

R’ = pL"/A"

R’ = p (L/2)⁄2A

R’= p L/4A

R’= ¼ x R

Answered by puniasarthak
16

Answer:1/4 =R

Explanation:

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