An ohmic conductor of circular cross-section has a resistance R. If it is melted and recast to half of its length with rectangular cross-section, its new resistance will be
Answers
Answered by
75
Answer:
R’= ¼ x R
Explanation:
Resistance of a wire is given as;
R = pL/A
Where p is the resistivity of wire. It will be same for same material
A is the cross sectional area
L is the length.
Now if the wire is recasted, such that the length is halved then, the area will also change because the overall volume has to be the same.
V’=V
A’ x L’ = A x L
When L’ = L/2
This means that area becomes;
A’ = 2 x A
Calculating new resistance of wire after it is recasted;
R’ = pL"/A"
R’ = p (L/2)⁄2A
R’= p L/4A
R’= ¼ x R
Answered by
16
Answer:1/4 =R
Explanation:
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