Physics, asked by amit2353, 1 year ago

An oil drop of mass m and charge q is to be held stationary in the gravitational field of the earth. What is the magnitude and direction of the electrostatic field required for this purpose?

Answers

Answered by Dahiya22
8

F=mg=-qE

So E= - mg/q

Here negstive sign signifies that the force is opp to the electic field This force on the oil drop act sin the down ward direction towards the earth.

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