An Oil Drop of mass m carrying charge -Q is to be held stationary in the gravitational field of the earth.what is the magnitude and direction of the electrostatic field required for his purpose ???
[ Grade 12 Physics ]
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HEYA!!
By the formula
mg=qE
=》 magnitude of oil drop=of oil drop × accelaration due to gravity
now according to formula
mg=-QE
sign of charge on oil drop will be -ve.
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