Question

An oil film of thickness 1.5 mm is used for lubrication between the square plates of size 0.9 m x 0.9 m inclined plane having an angle of inclination of 200. The weight of the square is 392.4 N and it slides down the plane with a uniform velocity of 0.2 m/s. Find the dynamic viscosity of the oil in poise.

Answer 1

Answer:

TIF F = Chi-107 and 2= (SP-39) then

calculate torque CT3 XF) .

A

Explanation:

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Answer 2

Explanation:

Given An oil film of thickness 1.5 mm is used for lubrication between the square plates of size 0.9 m x 0.9 m inclined plane having an angle of inclination of 200. The weight of the square is 392.4 N and it slides down the plane with a uniform velocity of 0.2 m/s. Find the dynamic viscosity of the oil in poise

• We need to find the dynamic viscosity of the oil.
• Now shear stress = τ = μ du / dy
•                     Force / unit area = μ du / dy
•                         Now F = 392.4 , A = 0.9 x 0.9 = 0.81 sq m, dy = 10 mm = 10 x 10^-3 m
•                            So F/A = 392.4 / 0.81
•                                        = 484.4
•                  So we  get
•                        F / A = μ du / dy
•                        484.4 = μ (0.2 / 0.01)
•                      Or 484.4 = μ 20
•                       Or μ = 484.4 / 20  
•                       Or μ = 24.22 Ns / m^2
•                               = 242.2 poise

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https://brainly.in/question/7564029