Math, asked by bikasghosh2, 10 months ago

An oil funnel made of tin sheet consists of a 10 cm long cylindrical portion attached to a frustum of a cone. If the total height is 22 cm , diameter of the cylindrical portion is 8 cm and the diameter of the top of the funnel is 18 cm, find the area of the tin sheet required to make the funnel.​

Answers

Answered by abhirock51
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( 5 Votes )

An oil funnel of tin sheet consists of a cylindrical portion 8 cm along attached to a frustum of a cone. If the total height be 15cm, the diameter of the cylindrical portion 1 cm and diameter of the top of the funnel 10cm, find the area of the tin required. [Take π=22/7]

Class 10th

KC Sinha - Mathematics

14. Surface Areas and Volumes

Answer

Diameter of top of funnel = 10cm

So, Radius (R) = 5cm

Diameter of cylindrical portion = 1cm

So,

Height of frustum = Total height – Height of cylindrical part

= 15 – 8

= 7cm

and Slant Height, l = √{h2 + (R – r)2}

= √{(7)2 +(5 – 0.5)2

= √49 + (4.5)2

= √49 + 20.25

= √69.25

= 8.32 cm

Now, CSA of frustum = πl (R + r)

= 143.81 cm2

Height of cylinder, H = 8cm

Now, CSA of cylinder = 2πrH

= 25.14 cm2

Area of tin required = CSA of frustum + CSA of cylinder

= 143.81 + 25.14

= 168.95 cm2

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