Question

An oil of kinematic viscosity 0.25 stokes flows through a pipe of diameter 10cm. The flow is critical at a velocity of

Answer 1

Answer:

0.5m/ s

Explanation:

I am solve your problems

Answer 2

The velocity is 0.5 m/s.

Explanation:

Given that,

Viscosity - 0.25 stokes

Diameter = 10 cm

We need to calculate the velocity

Using formula of viscosity

$R=\dfrac{\rho Dv}{\mu}$

$v=\dfrac{R\mu}{D\rho}$

Where, $\dfrac{\mu}{\rho}$ = kinematic viscosity

$\mu$ = viscosity

D = diameter

Put the value into the formula

$v=\dfrac{2000\times0.25\times0.0001}{10\times10^{-2}}$

$v=0.5\ m/s$

Hence, The velocity is 0.5 m/s.

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Topic : kinematic viscosity

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