Math, asked by bk378102, 6 months ago


An old man had 23 buffaloes. He wanted to give 1/3 of them to his eldest son, 1/3 of them to
the middle son and1/8
of them to the youngest son. How many buffaloes did each one of the son get?​

Answers

Answered by ghostnitin
1

Answer:

elder brother 7

middle bother 7

youngest brother 2

1/3 of 23 =7 in both

1/8 of 23= 2

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