Question

An old man moves in a semicircular track of radius 40 m during a morning walk. If he starts at one end of the track and reaches the other end , find the distance covered and displacement of the man

Answer 1

distance=40$\pi$ m
displacement= 80 m

Answer 2

Answer:

The distance covered by the an old man is 125.71 m and displacement of an old man is 80 m.

Explanation:

Radius of semicircular path = r = 40 m

Circumference of the circle = $2\pi r$

Circumference of the semicircle =$\frac{2\pi r}{2}=\pi r$

Distance covered by old man from one yo another :

$\pi r=\frac{22}{7}\times 40 m=125.71 m$

Displacement of the man, means shortest distance between both the ends.

Displace of the man = diameter of circle = 2 × radius = 2r = 80 m