Question

An old man walks 10 metres due east from his house and then turns to his left at an angle of 60 degree with the east and walks 10 metre in that direction and sits on a bench is cancelled after seeing him translate to him from a position the old man's started his journey how much distance his grandson travels to reach him and in what direction he ran

Answer 1

Answer:

There is no direct formula to solve this kind of questions.

Here,

Displacements of the old man are OA and OB,

|OA| = |AB| = 10 m

Displacement of the kid = OB

Now,

BC = AB sin60 = 10×√3/2 = 5√3

AC = AB cos60 = 10×1/2 = 5

In triangle OBA,

OB2 = OC2 + BC2

=> OB2 = (OA+AC)2 + BC2

=> OB2 = 152 + (5√3)2

=> OB2 = 225 + 75

=> OB = √300 = 10√3 m

This is the distance travelled by the kid.

Again,

tanθ = BC/OC

=> tanθ = (5√3)/15

=> θ = tan-1(1/√3) = 300

This is the direction of the displacement of the kid with the East direction.

Answer 2

Answer:

this is the ans

hope it will help you

thanks