an oleum sample labelled as 104.5%. in 10g of this sample 90mg of water is added then the resulting solution contains how much H2SO4
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When 100g oleum sample requires 4.5g water to produce 104.5g sulfuric acid, it is labelled as 104.5 % oleum.
Water required for 10g sample is 0.45g.
Free SO
3
=
18
80
×0.45=2g.
To this 10g sample, 90mg or 0.09g water is added. It will react with
18
80
×0.09=0.414g of SO
3
.
Amount of free SO
3
present now =2−0.414=1.586g. It is equal to
10
1.586
×100=15.86%.
Amount of sulfuric acid present in the solution =10+0.09−1.586=8.49g
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