Question

An open and closed organ pipe have the same length. The ratio of pth mode of frequency of vibration of two pipes is(a) 1(b) p(c) p(2p + 1)(d) $\frac{2p}{(2p-1)}$

Answer 1

Answer:

D) 2p/2p-1

Explanation:

Number of pipes = 2 open and closed (Given)

length = l = same (Given)

Therefore,

pth mode of vibration of open organ pipe n1 = p × v/2l

pth mode of vibration of closed organ pipe n2 = (2p-1)/2 × v/2l

Thus,

n1/n2 = (p × v/2l)/ (2p-1)/2 × v/2l

n1/n2 = 2p/2p-1

Thus, the ratio of pth mode of frequency of vibration of two pipes will

be =  2p/2p-1