Question

An open beaker at 27c is heated upto 477 degree c what fraction of air would have been expelled out

Answer 1

hello mate please

suppose at 27°c that is 300 k the volume is v.

but 477° c that is 750 k the volume is xv.

please use gas law

V1/T1 = V2/T2

V2 = V1 × T2 /T1

please put the given values

xv = v × 750 / 300

so the final volume is 2.5 v

so the volume expelled out = 2.5 - 1 = 1.5 v

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