An open box is made of wood 3 cm thick.Its external dimensions are 1.46m,1.16m and 8.3dm.Find the cost of painting the inner surface of the box at75 paise per 100cm
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Solution:-
External Length = 1.46 m
Inner Length = 1.46 m - (0.3 m + 0.3 m)
= 1.40 m or 140 cm
External Breadth = 1.16 m
Inner Breadth = 1.16 m - (0.3 m + 0.3 m)
= 1.10 m or 110 cm
External Height = 8.3 dm or 83 cm
Inner Height = 83 cm - 3 cm = 80 cm
Cost of painting = 75 paise per 100 sq cm
Cost of painting the bottom from inside = 140*110*(75/100)
= 11550 paise or Rs.115.50
Cost of painting the four sides = (2*140*80 + 2*80*110)*(75/100)
= (22400 + 17600)*(75/100)
= (40000*75)/100
= 30000 paise or Rs. 300
Total cost of painting from inside = Rs. 115.5 + Rs. 300
= Rs. 415.50
Answer.
External Length = 1.46 m
Inner Length = 1.46 m - (0.3 m + 0.3 m)
= 1.40 m or 140 cm
External Breadth = 1.16 m
Inner Breadth = 1.16 m - (0.3 m + 0.3 m)
= 1.10 m or 110 cm
External Height = 8.3 dm or 83 cm
Inner Height = 83 cm - 3 cm = 80 cm
Cost of painting = 75 paise per 100 sq cm
Cost of painting the bottom from inside = 140*110*(75/100)
= 11550 paise or Rs.115.50
Cost of painting the four sides = (2*140*80 + 2*80*110)*(75/100)
= (22400 + 17600)*(75/100)
= (40000*75)/100
= 30000 paise or Rs. 300
Total cost of painting from inside = Rs. 115.5 + Rs. 300
= Rs. 415.50
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