Question

an open box is made of wood 3 cm thick its external length 1.48 metre,breath 1.16 metre 18.3 decametre. find the cost of painting the inner surface of rupees 50 per square metre​

Answer 1

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Given thickness of wood = 3 cm Length of open box = 1.48 m = 148 cm Breadth of open box = 1.16 m = 116 cm Height of open box = 8.3 dm = 83 cm Inner length, l = outer length – twice width                           = 148 – 6 = 142 cm Outer breath = 116 – 6 = 110 cm Outer height = 83 – 3 = 80 cm [since it is an open box]Area of inner surface = 2(lb + bh + hl) – lb= 2[142 x 110 + 110 x 80 + 80 x 142] – [142 x 110] = 55940 sq cm Cost of painting inner surface = Rs (50/100) x (55940/100) = Rs 279.90

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Answer 2

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Given thickness of wood = 3 cm Length of open box = 1.48 m = 148 cm Breadth of open box = 1.16 m = 116 cm Height of open box = 8.3 dm = 83 cm Inner length, l = outer length – twice width = 148 – 6 = 142 cm Outer breath = 116 – 6 = 110 cm Outer height = 83 – 3 = 80 cm [since it is an open box]Area of inner surface = 2(lb + bh + hl) – lb= 2[142 x 110 + 110 x 80 + 80 x 142] – [142 x 110] = 55940 sq cm Cost of painting inner surface = Rs (50/100) x (55940/100) = Rs 279.90