Question

An open box is made of wood 3 cm thick. Its external length, breadth and height are 1.46 m, 1.16 m and 8.3 dm respectively. What is the cost of painting the inner surface of the box at 50p per 100 cm square.

Answer 1

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Given thickness of wood = 3 cm

Length of open box = 1.48 m = 148 cm

Breadth of open box = 1.16 m = 116 cm

Height of open box = 8.3 dm = 83 cm

Inner length, l = outer length – twice width

                          = 148 – 6 = 142 cm

Outer breath = 116 – 6 = 110 cm

Outer height = 83 – 3 = 80 cm [since it is an open box]

Area of inner surface = 2(lb + bh + hl) – lb

= 2[142 x 110 + 110 x 80 + 80 x 142] – [142 x 110]

= 55940 sq cm

Cost of painting inner surface = Rs (50/100) x (55940/100) = Rs 279.90