Math, asked by djpandey045, 9 months ago

an open box is made of wood 3cm thick. its external length, breadth, height are 1.46m, 1.16m, 8.3dm respectively. what is the cost of painting the inner surface of box at 50p per 100cm2

Answers

Answered by narissa050707
7

Answer:

Given thickness of wood = 3 cm Length of open box = 1.48 m = 148 cm Breadth of open box = 1.16 m = 116 cm Height of open box = 8.3 dm = 83 cm Inner length, l = outer length – twice width                           = 148 – 6 = 142 cm Outer breath = 116 – 6 = 110 cm Outer height = 83 – 3 = 80 cm [since it is an open box]Area of inner surface = 2(lb + bh + hl) – lb= 2[142 x 110 + 110 x 80 + 80 x 142] – [142 x 110] = 55940 sq cm Cost of painting inner surface = Rs (50/100) x (55940/100) = Rs 279.90

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