Math, asked by asthaagarwal851, 6 hours ago

An open box of length 1.7 m, breadth 1 m, and height 1.3 m is to be made for use on a trolley for collecting dry waste. How much sheet of metal will be required to make this box ?​

Answers

Answered by llFairyHotll
51

\huge\mathcal\colorbox{lavender}{{\color{b}{✿Yøur-ᎪղՏωᎬя}}}

➤Length of the box (l) = 1.5 m, breadth (b) = 1 m, height (h) = 1 m

Since, the box is open at top,

∴ Sheet required to make the box = total surface area of the box – area of the top

= 2 (lb + bh + lh) – lb

= 2lb + 2bh + 2lh – lb

= lb + 2bh + 2lh

= 1.5 × 1 + 2 × 1 × 1 + 2 × 1.5 × 1

= 1.5 + 2 + 3

= 6.5 sq. m.

Since the inside and outside surface of the box are to be painted.

∴ Area to be painted = 2 × Area of the box = 2 × 6.5 = 13 sq. m.

Total cost of painting = area to be painted × rate per sq. m.

= 13 × 150

= Rs 1950

∴ 6.5 sq. m. sheet of metal will be required and the cost of painting the box will be Rs 1950.

Hope it's helpful↑(◍•ᴗ•◍)❤࿐

Answered by Itzintellectual
0

Step-by-step explanation:

\mathcal\colorbox{lavender}{{\color{b}{✿Yøur-ᎪղՏωᎬя}}}

➤Length of the box (l) = 1.5 m, breadth (b) = 1 m, height (h) = 1 m

Since, the box is open at top,

∴ Sheet required to make the box = total surface area of the box – area of the top

= 2 (lb + bh + lh) – lb

= 2lb + 2bh + 2lh – lb

= lb + 2bh + 2lh

= 1.5 × 1 + 2 × 1 × 1 + 2 × 1.5 × 1

= 1.5 + 2 + 3

= 6.5 sq. m.

Since the inside and outside surface of the box are to be painted.

∴ Area to be painted = 2 × Area of the box = 2 × 6.5 = 13 sq. m.

Total cost of painting = area to be painted × rate per sq. m.

= 13 × 150

= Rs 1950

∴ 6.5 sq. m. sheet of metal will be required and the cost of painting the box will be Rs 1950.

Hope it's helpful↑(◍•ᴗ•◍)❤࿐

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