Science, asked by chandru17bala, 6 months ago

An open circular cylinder of 15cm diameter
and 100cm long contains water upto a height
of 70cm. Find the speed at which the cylinder
is to be rotated with an angular velocity of
59.05 rad/s about its vertical axis so that the
axial depth becomes zero.​

Answers

Answered by tripathiakshita48
0

Answer:The speed of the cyclinder is 4.43m/s

Explanation:

An open circular cylinder of 15cm diameter

and 100cm long contains water upto a height

of 70cm. Find the speed at which the cylinder

is to be rotated with an angular velocity of

59.05 rad/s about its vertical axis so that the

axial depth becomes zero.:-

So the solution is as follows that:-

the cyclinder is 15cm diameter and 100cm water till 70cm and also the angular velocity is 59.05rad/s and finally given that:-

the axis depth is zero so everything is in its standard and stable state so the formales are applicable and can be applied easily:-

v=rw;

radius is 7.5cm and the value of w is 59.05 so we get the speed which is:-

v=(7.5cm)(59.05)=442.875cm/s

equals 4.43m/s.

Answer:-The speed of the cyclinder is 4.43m/s

For more questions:-https://brainly.in/question/34438572

#SPJ1

Answered by KajalBarad
0

The speed at which the cylinder is to be rotated with an angular velocity of 59.05 rad/s about its vertical axis so that the axial depth becomes zero 4.43m/s.

Given;

Diameter of an open cylinder is 15cm,

Length of the cylinder = 100cm,

Angular velocity = 59.05 rad/s

axis depth = 0.

To Find;

The speed at which the cylinder is to be rotated with an angular velocity of 59.05 rad/s about its vertical axis so that the axial depth becomes zero.​

Solution;

The speed at which the cylinder is to be rotated with an angular velocity of 59.05 rad/s about its vertical axis so that the axial depth becomes zero 4.43m/s.

The axis depth is zero so everything is in its  stable state and standard state so the formulas are applicable and can be solved easily:-

v = rw;

where, v = velocity,

r - radius,

w - (omega) angular velocity

radius = 7.5cm

and the value of w is 59.05

so we get the speed which is:-

v = (7.5cm)(59.05)

 = 442.875cm/s

 = 4.43m/s. (After solving)

The speed of the cylinder is 4.43m/s

The speed at which the cylinder is to be rotated with an angular velocity of 59.05 rad/s about its vertical axis so that the axial depth becomes zero 4.43m/s.

#SPJ1

Similar questions