Question

An open conical tank of diameter 16m and 6m deep is to be made: (use π = 3.14)
> Find the area of metallic sheet required.
> What will be the cost of painting it's outer surface area at rate of RS. 5 per square metres..??

Answer 1

the ans of your question is given as above

Answer 2

Area is 452.16 $m^2$ & Cost of Painting is Rs. 2260.80 /-

Step-by-step explanation:

• Diameter of Tank (d) = 16 m

• So, radius of tank (r) = $\frac {d}{2}$

= $\frac {16}{2} = 8 m$

Height of Tank (h) = 6 m

(For the slant height, we need to apply pythagoras theorem. or )

Area of Metallic Sheet = $\pi r \times \sqrt {r^2+h^2} + \pi r^2$

= $\pi \times 8 \times (\sqrt {8^2+6^2} + 8)$

= $3.14 \times 8 (\sqrt {64 + 36} + 8)$

= $25.12 {\sqrt 100 + 8}$

= $25.12 (10 + 8)$

= $25.12 \times 18$

= 452.16 $m^2$

• Cost of painting its outer surface area at the rate of Rs. 5 per square meter = $452.16 \times 5$

= Rs. 2260.80