Question

an open cubical tank was initially fully filled with water. when the tank was accelerated on a horizontal plane along one of its side it was found that one third of volume spilled out?the acceleration was??? answer is 2g/3

Answer 1

Answer:

an open cubical tank was initially fully filled with water. when the tank was accelerated on a horizontal plane along one of its side it was found that one third of volume spilled out?the acceleration was

Answer 2

Thus the value of acceleration is a = 2 g /3

Explanation:

Given data:

• Let each side = H
• Volume of water spilled out =   1 / 3  × H^3  --- (1)
• The height of surface dipped = h

The volume of spilled liquid = area of triangle×side of cube =   1/2  ×h× H^2  --(2)

From equation (1) and (2).

 1 / 3  × H^3 =   1/2  ×h× H^2

h = 2 / 3 x h

angle θ = h / H

Now a = g x h / H

a = 2g / 3

Thus the value of acceleration is a = 2 g /3