Question

An open cubical tank was initially fully
filled with water. When the tank is
accelerated on a horizontal plane along
one of its edge it was found that one
third of volume of water spilled out.
The acceleration is
g​

Answer 1

Answer:

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Answer 2

The acceleration given to box will be 2g/3.                        

• As shown in fig, let the cube be of side L.

• Volume of water spilled out = (L^3)/3 ...(1)

• Let the surface of water in cube drops by height Y,

• Then, the volume of spilled liquid = area of triangle×side of cube

      = (1/2) × Y × L^2 ...(2)

• From (1) & (2),

       

       (L^3)/3 = (1/2) × Y × L^2

• Hence, Y = 2L/3.

• Let  the angle made by the surface with horizontal be θ, then

        tanθ = a/g

• From diagram,

       tanθ = Y/L

• So, a/g = Y/L

• Hence, a = 2g/3.