Question

an open cyclinder vessel whose length is 42 cm and daimeter is 28 cm is made up of metal sheet find the area of metal sheet required for making the vessel​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Metal\:sheet\:required=3696\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Length \: of \: cylinder = 42 \: cm} \\ \\ : \implies \text{Diameter \: of \: cylinder = 28\: cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: metal \: sheet\:required= ?}$

• According to given question :

$: \implies \text{C.S.A \: of \: cylinder = }2\pi rh \\ \\: \implies \text{C.S.A \: of \: cylinder = }2 \times \frac{22}{7} \times 14 \times 42 \\ \\ : \implies \text{C.S.A\: of \: cylinder = }2 \times 22 \times 2 \times 42 \\ \\ \green{: \implies \text{C.S.A \: of \: cylinder = }3696 {cm}^{2} } \\ \\ \green{\therefore \text{Metal \: sheet \: required = 3696 {cm}}^{2} }$

Answer 2

Answer

• Metal sheet required=3696 cm^2

Step-by-step-explanation

$\implies \text{c.s.a \: of \: cylinder = }2\pi rh \\ \\ \implies \text{c.s.a \: of \: cylinder = }2 \times \frac{22}{7} \times 14 \times 42 \\ \\ \implies \text{c.s.a \: of \: cylinder = }2 \times 22 \times 2 \times 42 \\ \\ \implies \text{c.s.a \: of \: cylinder = }3696 {cm}^{2}$