Question

an open cylindrical tank has a diameter of 3.5 metre and height of 7m .how much will it cost to paint the curved surface and the base of the tank if the rate of painting is 5.00 per metre square.​

Answer 1

Step-by-step explanation:

we have to find the cost of painting the it's curved surface area and base.

so we will use CSA+1b formula.

given diameter is 3.5m

therefore radius is 3.5/2

=1.75m

height is 7m

CSA+1b of the tank=2πrh+πr²

=(2×22/7×1.75×7)+(22/7×1.75×1.75)

=(44×1.75)+(67.375/7)

=77+67.375/7

=539+67.375/7

=606.375/7

=86.625m²

cost of painting if per m² costs ₹5=86.625×5

=₹433.125

hope this helps..!

Answer 2

Answer:

The C.S.A of Cylinder is 86.54.$m^{2}$..The rate of painting the cylindrical tank is ₹432.7

Step-by-step explanation:

Diameter = 3.5m.

Radius = 3.5m/2

           = 1.75m

Height -= 7m

Area to be painted  = 2πrh + π$r^{2}$

                              = 2 x 3.14 x 1.75 x 7 + 3.14 x 1.75 x 1.75

                              = 76.93$m^{2}$ + 9.61

                              = 86.54.$m^{2}$

The rate of painting the cylinder = ₹5 x 86.54.$m^{2}$

                                                       = ₹432.7