Question

An open cylindrical tank has a diameter of 3.5m and height of 7m. how much will it cost to paint the curved surface and the base of the tank if the rate of painting is Rs 5.00 per m2

Answer 1

hello frnd!

here's ur answer...

we have to find the cost of painting the it's curved surface area and base.

so we will use CSA+1b formula.

given diameter is 3.5m

therefore radius is 3.5/2

=1.75m

height is 7m

CSA+1b of the tank=2πrh+πr²

=(2×22/7×1.75×7)+(22/7×1.75×1.75)

=(44×1.75)+(67.375/7)

=77+67.375/7

=539+67.375/7

=606.375/7

=86.625m²

cost of painting if per m² costs ₹5=86.625×5

=₹433.125

hope this helps..!

Answer 2

☆Hello friend☆

Lets take out area of curved part of cylinder whose formula=
$2\pi \: rh$
=2×22/7 ×3.5/2 m×7m
=2×22×0.5m×7m
=77m^2

Cost of painting per sq. m= Rs 5
Cost of painting 77 m^2= 77×Rs 5
= Rs 385
Area of base= 22/7×r^2
=22/7×3.5m/2×3.5m/2
=11×0.5m×1.75.
=9.625m^2
Cost of base=9.625×5
=Rs 48.1
Total cost= 385+48.1=
Rs433.1

Plz mark its a brainliest if it was helpful.

☺☺☺